A piece of ice (heat capacity = 2100 J kg –1 ºC –1 and latent heat = 3.36 × 10 5 J kg –1 ) of mass m grams is at –5 ºC at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally, when the ice-water mixture is in equilibrium, it is found that 1 gm of ice has melted. Assuming there is no other heat exchange in the process, the value of m is:
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(8 gm)
Sol. S = 2100 J kg –1 ºC –1
L = 3.36 × 10 5 J kg –1
420 = m S Δθ + × 10 –3 × L
420 = m S (5) + 3.36 × 10 2
420 – 336 = m (2100) × 5
m = 
× 1000 = 8 gm.
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